Question

6x^2-x-1 solve this​

Answer 1

Answer:

$\bf\ x = \frac{1}{2} \: and \: \frac{ - 1}{3}$

Step-by-step explanation:

$\bf\huge \: {6x}^{2} - x - 1 = 0 \\ \\ \sf\red{ \underline{using \: the \: middle \: term \: method}} \\ \\ \tt\ \implies: {6x}^{2} - (3x - 2x) - 1 = 0 \\ \\ \tt\ \implies: {6x}^{2} - 3x + 2x - 1 = 0 \\ \\\tt\ \implies: 3x(2x - 1) + 1(2x - 1) = 0 \\ \\ \tt\ \implies:(3x + 1)(2x - 1) = 0 \\ \\ \bf\ \bigstar 3x + 1 = 0 \\ \tt\boxed{ \implies: x = \frac{ - 1}{3} }\\ \\ \bf\ \bigstar2x - 1 = 0 \\\tt\boxed{ \implies:x = \frac{1}{2} }$

Answer 2

Answer:

$\huge\sf\underline\mathtt\red{Answer:}$

check the above attachment!

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