Question

6x^2+-x-2=0find the roots​

Answer 1

Step-by-step explanation:

$6 {x}^{2} - x - 2 = 0$

$6 {x}^{2} + 3x - 4x - 2 = 0$

$3x(2x + 1) + 2(2x + 1) = 0$

$(3x + 2)(2x + 1) = 0$

so the roots are

x= -2/3,-1/2

hope this will help u

Answer 2

Answer:

x=-2/3;1/2

Step-by-step explanation:

6x^2+x-2=0

6x^2+4x-3x-2=0

2x(3x+2)-1(3x+2)=0

3x+2=0;2x-1=0

3x=-2;2x=1

x=-2/3;x=1/2

x=-2/3;1/2