Question

6x + 2 + x2 + 12x2 + 2x

Answer 1

We have,
6x+2+x²+12x²+2x
6x+2x+x²+12x²+2. (by rearranging)
8x+13x²+3


Please mark my answer brainliest!
thanks!

Answer 2

Answer:

Step-by-step explanation:

Given

f(x) = 6x+2+x²+12x²+2x

f(x) = 6x+2x+x²+12x²+2

f(x) = 8x+3

or f(x) = 13x²+ 8x+3

Solve this equation by quadratic formula

x= -b±(√b²-4ac) / 2 a

where

b= coefficient of x = 8

a = coefficient of x²= 13

c= constant = 3

D= b²-4ac= (8)²-4(13*3)

= -92< 0

Hence the roots of the equation are non real because D < 0