Question

6x +29 =5 ÷x please answer this question​

Answer 1

$\huge { \underline{ \underline{ \mathbb\red{{ANSWER}}}}}$

$6x + 29 = 5 \div x \\ \\ \implies 6 {x}^{2} + 29x = 5 \:\:\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \implies 6 {x}^{2} + 29x - 5 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \implies6 {x}^{2} + 30x - x - 5 = 0 \: \: \: \: \: \\ \\ \implies 6x(x + 5) - 1(x + 5) = 0 \\ \\ \implies (x + 5)(6x - 1) = 0 \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \implies \boxed{x = - 5 \: \bold{and} \: x = \frac{1}{6} }\: \: \: \: \: \: \: \: \:$

Answer 2

Answer:

6x+29=5÷x

6x^2+29x=5

6x^2+29x-5=0

6x^2+30x-x-5=0

6x(x+5)-1(x+5)=0

(x+5)(6x-1)=0

HOPE THIS HELPS YOU

PLEASE MARK ME AS BRAINLIEST

PLEASE FOLLOW ME