Math, asked by sharmasamriti64, 1 month ago

6x-2y-9=0, 3x-y+12=0​

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Answered by rashinitoppr
1

Answer:

parallel The given equations are as follows: 6x - 2y + 9 = 0 and 3x - y + 12 = 0 They are of the following form: a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0 Here, a1 = 6, b1 = -2, c1 = 9 and a2 = 3, b2 = -1 and c2 = 12 The given system has no solution. Hence, the lines are parallel. -6x-2y-9-0-and-3x-12-0-are-two-lines-which-are-a-coincident-parallel

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