Question

6x^3 - 23x^2 + 29x - 12​

Answer 1

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

(((6 • (x3)) - 23x2) + 29x) - 12

STEP

2

:

Equation at the end of step

2

:

(((2•3x3) - 23x2) + 29x) - 12

STEP

3

:

Checking for a perfect cube

3.1 6x3-23x2+29x-12 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 6x3-23x2+29x-12

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 29x-12

Group 2: 6x3-23x2

Pull out from each group separately :

Group 1: (29x-12) • (1)

Group 2: (6x-23) • (x2)