6x^3+29x^2+38x + 21-a divided by 3x+ k
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Answer:
Step-by-step explanation: Let A be the other polynomial. It is given that one of the polynomial is 3x+7 and the product of the polynomials is 6x
3
+29x
2
+44x+21 that is:
(3x+7)×A=6x
3
+29x
2
+44x+21
A=
3x+7
6x
3
+29x
2
+44x+21
We now divide 6x
3
+29x
2
+44x+21 by (3x+7) as shown below:
From the division, we observe that the quotient is 2x
2
+5x+3 and the remainder is 0.
Hence, the other polynomial is 2x
2
+5x+3.
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