Question

6x^-3-7x find the zeros and verify it

Answer 1

Hey Mate ✌

Here's your answer friend,

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==> 6x² - 7x - 3

==> 6x² - 9x + 2x - 3 = 0

==> 3x(2x - 3) + 1(2x - 3) = 0

==> (3x + 1)(2x - 3) = 0

==> x = -1/3 or x = 3/2

Now, Verification =============>

On comparing above equations we get,

a = 6, b = -7, c = -3

==> Let α = -1/3 and β = 3/2

==> Sum of the zeroes,

==> α + β = -b/a

==> LHS = -1/3 + 3/2

==> LHS = -2 + 9 / 6

==> 7 / 6

Now RHS = -b / a

==> -(-7)/6

==> 7/6

LHS = RHS

Now product of zeroes,

==> αβ = c/a

==> LHS = αβ

==> -1/3 X 3/2

==> -3/6

==> -1/2

RHS = c/a

==> -3/6

==> -1/2

LHS = RHS

Hence, Verified.

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Hope it helps you ☺☺☺