6x^3+x^2+6-19x by 2*3
using long division method ...
plz answer fast because it is very very urgent. I need step by step ... plz answer me.
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Step-by-step explanation:
6x^3+x^2+6-19x
Rearrange 6x^3+x^2-19x+6
To catch the zeroes for the above cubuic equation
let check what will be the zeroes for the given equation
x=-2
sustitue and see the zeroes of equation
6(-2)^3+(-2)^2-19(-2)+6=0
-48+4+6+(38)=0
-38+38=0
0==0
hece verified that x=-2
x+2=0 where it is the factor of the cubic equation
by using long division
x+2)6x^3+x^2-19x+6(6x^2-11x+1
6x^3+12x^2
___-____-______
- 11x^2-19x
-11x^2-22x
_______+____+______
6x+6
6x+6
_________-___-______
0
hence , complete d
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