Question

6x^3+x^2+6-19x by 2*3
using long division method ...

plz answer fast because it is very very urgent. I need step by step ... plz answer me.
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Answer 1

Step-by-step explanation:

6x^3+x^2+6-19x

Rearrange 6x^3+x^2-19x+6

To catch the zeroes for the above cubuic equation

let check what will be the zeroes for the given equation

x=-2

sustitue and see the zeroes of equation

6(-2)^3+(-2)^2-19(-2)+6=0

-48+4+6+(38)=0

-38+38=0

0==0

hece verified that x=-2

x+2=0 where it is the factor of the cubic equation

by using long division

x+2)6x^3+x^2-19x+6(6x^2-11x+1

6x^3+12x^2

___-____-______

- 11x^2-19x

-11x^2-22x

_______+____+______

6x+6

6x+6

_________-___-______

0

hence , complete d