6x +3y =6xy and 2x +4y =5xy in substitution method . I will mark u as a brainlist
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Answer :
x = 1 , y = 2
Solution :
Here ,
The given equations are ;
6x + 3y = 6xy ------(1)
2x + 4y = 5xy ------(2)
Now ,
Considering eq-(1) , we have ;
=> 6x + 3y = 6xy
=> 3(2x + y) = 6xy
=> 2x + y = 6xy/3
=> 2x + y = 2xy
=> 2x/xy + y/xy = 2
=> 2/y + 1/x = 2
=> 1/x = 2 - 2/y --------(3)
Now ,
Considering eq-(2) , we have ;
=> 2x + 4y = 5xy
=> 2x/xy + 4y/xy = 5
=> 2/y + 4/x = 5 -------(4)
Now ,
Substituting 1/x = 2 - 2/y in eq-(4) , we get ;
=> 2/y + 4/x = 5
=> 2/y + 4•(1/x) = 5
=> 2/y + 4•(2 - 2/y) = 5
=> 2/y + 8 - 8/y = 5
=> 8 - 5 = 8/y - 2/y
=> 3 = (8 - 2)/y
=> 3 = 6/y
=> y = 6/3
=> y = 2
Now ,
Putting y = 2 in eq-(3) , we get ;
=> 1/x = 2 - 2/y
=> 1/x = 2 - 2/2
=> 1/x = 2 - 1
=> x = 1
Hence ,
x = 1 , y = 2
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