6x+3y=6xy or 2x+4y=5xy
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Answered by
117
1st Equation : 6x + 3y = 6xy --------------- (1)
2nd Equation : 2x + 4y = 5xy -------------- (2)
On solving (1) & (2) * 3, we get
6x + 12y = 15xy
6x + 3y = 6xy
-------------------------
9y = 9xy
x = 1.
Substitute x = 1 in (1), we get
6x + 3y = 6xy
6(1) + 3y = 6(1)(y)
6 + 3y = 6y
6 = 6y - 3y
6 = 3y
y = 2.
Therefore x = 1 and y = 2.
Hope this helps!
2nd Equation : 2x + 4y = 5xy -------------- (2)
On solving (1) & (2) * 3, we get
6x + 12y = 15xy
6x + 3y = 6xy
-------------------------
9y = 9xy
x = 1.
Substitute x = 1 in (1), we get
6x + 3y = 6xy
6(1) + 3y = 6(1)(y)
6 + 3y = 6y
6 = 6y - 3y
6 = 3y
y = 2.
Therefore x = 1 and y = 2.
Hope this helps!
Answered by
41
Solution :
Given equations are,
6x+3y=6xy _____(1)
2x+4y=5xy _____(2)
From eq (1) and (2) ×3
We get,

9y-9xy = 0
9y(1-x) = 0
y(1-x) = 0
=> y = 0 or x = 1
1) If y = 0,
From (i) we get,
6x+3(0) = 6x(0)
6x = 0
=> x = 0
2) If x = 1
From (i) we get,
6(1)+3y = 6(1)y
=> 6 = 6y-3y
=> 3y = 6
=> y = 2
Hence,
x = 0 , y = 0
OR
x = 1 , y = 2
Given equations are,
6x+3y=6xy _____(1)
2x+4y=5xy _____(2)
From eq (1) and (2) ×3
We get,
9y-9xy = 0
9y(1-x) = 0
y(1-x) = 0
=> y = 0 or x = 1
1) If y = 0,
From (i) we get,
6x+3(0) = 6x(0)
6x = 0
=> x = 0
2) If x = 1
From (i) we get,
6(1)+3y = 6(1)y
=> 6 = 6y-3y
=> 3y = 6
=> y = 2
Hence,
x = 0 , y = 0
OR
x = 1 , y = 2
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