6x+3y=6xyand 2x+4y=5xyusing elimination method
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X= 6
y= 12/11
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Answer:
given
eq1: 6x+3y=6xy
eq2: 2x+4y=5xy
multiply eq2 with 3
we get, 6x+4y=15xy
now, subtract eq1 from eq2
we get, 6x+12y=15xy - 6x+3y=6xy
=》9y=9xy
=》9y/y=9x
=》9=9x
=》9/9=x
eq3:1=x
substitute eq3 in eq1
we get, 6(1)+3y=6(1)y
=》 6+3y=6y
=》6=6y-3y
=》6=3y
=》6/3=y
=》2=y
therefore the value of x =1 and y=2
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