6x /4 -6x sq +2x+11 ÷x-2
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Answered by
0
Answer:
∫(x
6
+x
4
+x
2
)
2x
4
+3x
2
+6
dx=∫(x
5
+x
3
+x)
2x
6
+3x
4
+6x
2
dx
Let 2x
6
+3x
4
+6x
2
=t
∴dt=12(x
5
+x
3
+x)
⟹∫(x
6
+x
4
+x
2
)
2x
4
+3x
2
+6
dx=∫
12
1
t
dt
=
12
1
×
3
2
t
2
3
+c
=
18
1
(2x
6
+3x
4
+6x
2
)
2
3
+c
⟹β+γ−α=7
Answered by
0
I hope it's hepls.
check the images
this → side slide and check images
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