6x+4y_z+3 and 2x_3y_2z+4
Answers
Answered by
0
Given system of linear equations are
2x + 3y + 3z = 5
x - 2y +z = -4
3x - y2z = 3.
Represent it in matrix form
3 -2 -1 3 1 X y 5 -4 which is in the 3 1 3 form of AX = B
Feedback
2 1 3 3 -2 -1 A = 3 1 2 N
|A| = 10 + 15 + 15 = 40 / 0
... A-¹ exists
To find adjoint of A
A11 = 5, A12 = 5, A13 = 5
Feedback
A213, A22 = -13, A23 = 11
A319, A32 = 1, A33 = -7
A-¹ -1 1 |A| Adj (A)
[5 5 5 3 -13 11 9 1 -7 1 40
Feedback
X = A=¹B
5 5 5 3 -13 11 9 1 5 -4 3 1 40
[25-12+27
X = A ¹B
1
40
-13
5 5 3 9 1 -7 5 -4 3 11
5
[25-12 +27 25 +52 +3 25 - 44 - 21 1 40
Feedback
40 80
X 1 40
40 81
X 2 Z
Hence, x = 1, y
Similar questions