Question

6x^5+4x^4-27x^3-7x^2+37x is divided by (2x^2-4​

Answer 1

Answer:

quotient =3x^3+2x^2-15x/2+1/2 remainder =7x+2

Step-by-step explanation:

To verify

divisor ×quotient +remainder =dividend

(2x^2-4)(3x^3+2x^2-15x/2+1/2)+7x+2

=6x^5+4x^4-15x^3+x^2-(12x^3+8x^2-30x+2)+7x+2

=6x^5+4x^4-27x^3-7x^2+37x=dividend

hence verify

hope it helps