6x^5+4x^4-27x^3-7x^2+37x is divided by (2x^2-4
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Answer:
quotient =3x^3+2x^2-15x/2+1/2 remainder =7x+2
Step-by-step explanation:
To verify
divisor ×quotient +remainder =dividend
(2x^2-4)(3x^3+2x^2-15x/2+1/2)+7x+2
=6x^5+4x^4-15x^3+x^2-(12x^3+8x^2-30x+2)+7x+2
=6x^5+4x^4-27x^3-7x^2+37x=dividend
hence verify
hope it helps
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