Math, asked by riddhikavekariya, 8 months ago

6x-5y=1. 5x-4y=8
find the values of x and y​

Answers

Answered by Anonymous
3

Answer:

6x - 5y = 1

6x = 5y + 1

x =  \frac{5y + 1}{6}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  -  -  - (1)

5x - 4y = 8

5( \frac{5y+ 1}{6} ) - 4y = 8 \\  \\ 5(5y + 1) - 24y  = 48 \\ 25y + 5 - 24y = 48 \\ y + 5 = 48 \\ y = 48 - 5\\ y = 43

Put y = 43 in eq(1)

x =  \frac{5(43) + 1}{6}  \\  \\ x =  \frac{215 + 1}{6}  \\  \\ x =  \frac{216}{6} \\  \\ x = 36

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Answered by Motherflipper
0

Answer:

Step-by-step explanation:

6x-5y=1

6x=1+5y

X=1+5y/6

So,=> 5x-4y=8 = 5*1+5y/6 - 4y=8

5+y/6=8

y=8*6-5

= 48-5

=43

Y= 43

Then,6x-5y=1 = 6x-5*43=1

6x-215= 1

6x=216

X=216/6

X=36

X=36,Y=4

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