6x + 5y = 7x+3y + 1 = 2(x + 6y - 1)
Find the value of x & y by substitution method
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Answer:
x = 3, y = 2
Step-by-step explanation:
We have:
6x + 5y = 7x + 3y + 1 = 2(x + 6y - 1).
(i) 6x + 5y = 2(x + 6y - 1)
(ii) 6x + 5y = 7x + 3y + 1.
On solving equation (ii), we get
⇒ 6x + 5y = 7x + 3y + 1
⇒ -x + 2y = 1
⇒ x - 2y = -1
⇒ x = 2y - 1 ----- (iii)
Substitute x = 2y - 1 in (i), we get
⇒ 6x + 5y = 2(x + 6y - 1)
⇒ 6x + 5y = 2x + 12y - 2
⇒ 4x - 7y = -2
⇒ 4(2y - 1) - 7y = -2
⇒ 8y - 4 - 7y = -2
⇒ y = 2
Substitute y = 2 in (iii), we get
⇒ x = 2y - 1
⇒ x = 3
∴ The values of x & y are 3 and 2
Hope it helps!
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