6x-7/4+3x-5/7=5x+78/28
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Answer:
(6x-7)/4 + (3x-5)/7 = (5x+78)/28
Equate the equation to 0
(6x-7)/4 + (3x-5)/7 - (5x+78)/28 = 0
Get the LCD of the denominators 4,7 and 28
The LCD is 28
Divide the denominator of each term to the LCD
28 [(6x-7)/4 + (3x-5)/7 - (5x+78)/28 ] 28 = 0
7(6x-7) + 4 (3x-5) - 1(5x+78) = 0
42x - 49 + 12x - 20 - 5x - 78 = 0
Combine like terms
49x - 147 = 0
transpose -147 to get the value of x
49x/49 = 147/49
x = 3
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