Question

(6x-7)/4+(3x-5)/7=(5x+78)/28

Answer 1

Answer:

6x-7)/4+(3x-5)/7=(5x+78)/28 answer

Answer 2

Answer:

Multiply both sides of the equation by 28, giving:

6x−74×28+3x−57×28=5x+7828×28

⇒(6x−7)×7+(3x−5)×4=(5x+78)

Multiply out the terms in parentheses, giving us:

42x−49+12x−20=5x+78

We now want all the terms with an x on one side of the equation and all the other terms on the other side of the equation. We can achieve this by:

Subtracting 5x from both sides

Adding (49+12) to both sides

This gives us: 42x+12x−5x=78+49+20

Adding up both sides: 49x=147

Dividing both sides by 49, we have:

x=14749=21×77×7=3×7×77×7

Cancelling the like terms from the denominator and numerator, we get:

x=3