Question

6x + 7y = 11
5x + 2y = 13
solve by cofficent method​

Answer 1

$\huge\textbf\red{An}\textbf\blue{sw}\textbf\green{er}$

$given \: question \\ solve \\ 6x + 7y = 11 \\ 5x + 2y = 13$

$By \: eliminating \: y \: term$

|6x+7y=11|×2

|6x+7y=11|×2|5x+2y=13|×7

$|6x+7y=11|×2 \\ </strong></h3><h3><strong>[tex]|6x+7y=11|×2 \\ |5x+2y=13|×7$

$12x+14y=22 \\ </strong></p><p><strong>[tex]12x+14y=22 \\ 35x+14y=91$

$\: \: \: \: \: \: \: \: \: \: \: \: 12x+14y = 22 \\ </strong></p><p><strong>[tex] \: \: \: \: \: \: \: \: \: \: \: \: 12x+14y = 22 \\ (-) -35x-14y = - 91\\ \: \: - 23x = - 69 \\ x = 3$

$substitute \: in \: the \: equation \: \\ 5x+2y=13$

$5(3)+2y=13$

$15+2y=13 \\ 2y=13-15 \\ y=-2$

$\huge\fbox\red{x=3,y=-2}$

Answer 2

Answer:

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Explanation:

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