Question

6x + 8y = 1/10 and 26x + 48y = 1/2 solve this equation

Answer 1

please refer to attachment

Answer 2

$6x+8y = \frac{1}{10}$

/* Multiplying each term by 10, we get */

$\implies 60x + 80y = 1 \: ---(1)$

$26x + 48y = \frac{1}{2}$

/* Multiplying each term by 2 , we get */

$\implies 52 x + 96 y = 1 \: ---(2)$

/* Subtract equation (2) from equation (1) , we get */

$8x - 16y = 0$

$\implies 8x= 16y$

$\implies x = 2y \: --(3)$

$Put \:x = 2y \: in \: equation \: (1), we \:get$

$60 \times 2y + 80y = 1$

$\implies 120y + 80y = 1$

$\implies 200y = 1$

$\implies y = \frac{1}{200} \: --(4)$

/* Put value of y in equation (3) , we get */

$x = 2 \times \frac{1}{200}$

$\implies x = \frac{1}{100}$

Therefore.,

$\green { x = \frac{1}{100} \:and \: y = \frac{1}{200} }$

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