6x squar minus seven x minus three find zeros and relationships between them
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6x² - 7x - 3 = 0
6x² - 9x + 2x - 3 = 0
3x(2x-3) + 1(2x-3) = 0
(2x-3)(3x+1) = 0
2x-3 = 0 OR 3x+1=0
2x= 3 3x=-1
x= 3/2 x= -1/3
SUM OF ZEROS
3/2 + (-1/3)
9/6 - 2/6
7/6
-b/a
-coefficient of x / coefficient of x²
PRODUCT OF ZEROS
3/2 • -1/3
-1/2
-3/6
c/a
constant term / coefficient of x²
HOPE IT HELPS !!!!
6x² - 9x + 2x - 3 = 0
3x(2x-3) + 1(2x-3) = 0
(2x-3)(3x+1) = 0
2x-3 = 0 OR 3x+1=0
2x= 3 3x=-1
x= 3/2 x= -1/3
SUM OF ZEROS
3/2 + (-1/3)
9/6 - 2/6
7/6
-b/a
-coefficient of x / coefficient of x²
PRODUCT OF ZEROS
3/2 • -1/3
-1/2
-3/6
c/a
constant term / coefficient of x²
HOPE IT HELPS !!!!
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