6X square + 17 X + 5 is equal to zero
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6x^2+17x+5=0
=)6x^2+15x+2x+5=0
=)3x(2x+5) +1(2x+5)=0
=)(3x+1)(2x+5)=0
x= -1/3 or -5/2
=)6x^2+15x+2x+5=0
=)3x(2x+5) +1(2x+5)=0
=)(3x+1)(2x+5)=0
x= -1/3 or -5/2
Answered by
0
here you go ☆☆
▪![6 {x}^{2} + 17x + 5 = 0 6 {x}^{2} + 17x + 5 = 0](https://tex.z-dn.net/?f=6+%7Bx%7D%5E%7B2%7D+%2B+17x+%2B+5+%3D+0)
▪![{b}^{2} - 4ac {b}^{2} - 4ac](https://tex.z-dn.net/?f=+%7Bb%7D%5E%7B2%7D+-+4ac)
▪![{17}^{2} - 4 \times 6 \times 5 = 169 {17}^{2} - 4 \times 6 \times 5 = 169](https://tex.z-dn.net/?f=+%7B17%7D%5E%7B2%7D+-+4+%5Ctimes+6+%5Ctimes+5+%3D+169)
now,
▪![x = \frac{ - b( - + ) { \sqrt{ {b}^{2} - 4ac } } }{2a} x = \frac{ - b( - + ) { \sqrt{ {b}^{2} - 4ac } } }{2a}](https://tex.z-dn.net/?f=x+%3D+%5Cfrac%7B+-+b%28+-+%2B+%29+%7B+%5Csqrt%7B+%7Bb%7D%5E%7B2%7D+-+4ac+%7D+%7D+%7D%7B2a%7D+)
▪![x = \frac{ - 17 ( + - ) \sqrt{169} }{2 \times 6} x = \frac{ - 17 ( + - ) \sqrt{169} }{2 \times 6}](https://tex.z-dn.net/?f=x+%3D+%5Cfrac%7B+-+17+%28+%2B+-+%29+%5Csqrt%7B169%7D+%7D%7B2+%5Ctimes+6%7D+)
▪![x = \frac{ - 17 + 13}{12} ... \frac{ - 17 - 13}{12} x = \frac{ - 17 + 13}{12} ... \frac{ - 17 - 13}{12}](https://tex.z-dn.net/?f=x+%3D+%5Cfrac%7B+-+17+%2B+13%7D%7B12%7D+...+%5Cfrac%7B+-+17+-+13%7D%7B12%7D+)
▪![x = \frac{ - 4}{12} .. \frac{ - 30}{12} x = \frac{ - 4}{12} .. \frac{ - 30}{12}](https://tex.z-dn.net/?f=x+%3D+%5Cfrac%7B+-+4%7D%7B12%7D+..+%5Cfrac%7B+-+30%7D%7B12%7D+)
▪![x = \frac{ - 1}{3} .. \frac{ - 15}{6} x = \frac{ - 1}{3} .. \frac{ - 15}{6}](https://tex.z-dn.net/?f=x+%3D+%5Cfrac%7B+-+1%7D%7B3%7D+..+%5Cfrac%7B+-+15%7D%7B6%7D+)
hope it helps you.......
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hope it helps you.......
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