Question

6x square +17x+5 =(3x+1) (..... )​

Answer 1

Refer the attachment Mate...

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Answer 2

Answer: $(3x+1)(2x+5)$

Step-by-step explanation: There are many ways to solve this, but the following may be simple to understand:

Since the square coefficient is not 1, you should amplify by 6 resulting$6x^2+17x+5=\dfrac{6}{6}\cdot(6x^2+17x+5)=\dfrac{36x^2+17(6x)+30}{6}$

then you can proceed as usual, taking two numbers that mutiplied give 30 and its sum 17. These numbers are 15 and 2 so

$36x^2+17(6x)+30=(6x+2)(6x+15)=2(3x+1)\cdot 3(2x+5)=6(3x+1)(2x+5)$

finally you get

$6x^2+17x+5=\dfrac{36x^2+17(6x)+30}{6}=\dfrac{6(3x+1)(2x+5)}{6}=(3x+1)(2x+5)$