Question

6x square + 19x + 10 = 0. by quadratic formula method​

Answer 1

Step-by-step explanation:

6x^2+19x+10=0

Here, a= 6 , b= 19 , c= 10

then, D = b^2 -4 a c

=> (19)^2 - 4 × 6 × 10

=> 361 - 24 × 10

=> 361 - 240

=> 121.

Therefore, alpha= -b + root 121 / 2 × a

= - 19 + 11 / 2 × 6

= - 8 / 12

= -2 / 3

and , beta= - b - root 121 / 2 × a

= -19 - 11 / 2 × 6

= - 30 / 12

= - 5 / 2

Hence, - 2 / 3 and -5 / 2 is the root of the given equation.