Question

6x square -4x+1=0
$6 {x}^{2} - 4x + 1 = 0$
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Answer 1

Answer:

$6x {}^{2} - 4x + 1 = 0 \\ using \: qudratic \: formulae \\ we \: have \: \\ d = {b}^{2} - 4ac \\ \: \: = ( - 4) {}^{2} + (- 4)(6)(1) \\ \: \: = 16 -24 \\ \: \: = - 8 < 0 \: it \: means \: no \: real \: roots \: axist$