Question

6x square +under root 5-6=0​

Answer 1

Answer:

${6x}^{2} + \sqrt{5 - 6} = 0 \\ {6}^{2} \times {x}^{2} \sqrt{5 - 6} = 0 \\ 36 \times {x}^{2} \sqrt{ - 1 = 0 } \\ 36 \times {x}^{2} = 0 \\ {x}^{2} = \frac{0}{36} \\ {x}^{2} = 0 \\ {x}^{2} = \sqrt{0}$