6x square +yz by 3xy
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(6x^2 + yz)/3xy
= (6x^2/3xy) + (yz/3xy)
= (2x/y) + (z/3x)
Therefore,the value of (6x^2 + yz)/3xy is 2x/y + z/3x
Hope this will help you
= (6x^2/3xy) + (yz/3xy)
= (2x/y) + (z/3x)
Therefore,the value of (6x^2 + yz)/3xy is 2x/y + z/3x
Hope this will help you
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