Question

6x+y=2
3x-4y=10

Solve for substitution
Needs to be (_,_)

Answer 1

GIVEN :

6x + y = 2________(1)

3x - 4y = 10_______(2)


From (1) ;

6x + y = 2

so, y = 2 - 6x


SUBSTITUTING the value of y in (2), we get

3x - 4y = 10

or, 3x - 4(2 - 6x) = 10

or, 3x - 8 + 24x = 10

or, 27x = 18

or, x = 18/27 = 2/3

So, x = 2/3


Putting the value of x we have

y = 2 - 6x = 2 - 6×(2/3) = 2 - 4 = -2


Hence, x = 2/3 & y = -2

Answer 2

Answer:

Given:

We have been given two equations:

6x+y=2

3x-4y=10

To Find:

We need to find the values of x and y.

Solution:

We have two equations :

6x+y=2______(1)

3x-4y=10_____(2)

We can write the first equation as:

6x + y = 2

or y = 2 - 6x___(3)

Substituting the value of y from equation 3 in equation 2 we get,

3x - 4(2 - 6x) = 10

=> 3x - 8 + 24x = 10

=> 27x - 8 = 10

=> 27x = 10 + 8

=> 27x = 18

=> x = 18/27____(4)

or x = 2/3 [cancellation by 3]

Now, substituting the value of x from equation 4 in equation 1 we have,

y = 2 - 6x

=> y = 2 - 6(2/3)

=> y = 2 - 4

=> y = -2

Hence, the value of x is 2/3 and value of y is -2.