6x +y when x=4 and y=8 is 32
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Answered by
1
Hello there! How is your day going?
First, let's rewrite our problem.
"Find 6x + y when x = 4 and y = 8."
Basically, we need to substitute x with 4 and y with 8.Let's do so.
6(4) + 8 is now our expression. To simplify it, we need to apply PEMDAS:ParenthesisExponentsMultiplicationDivisionAdditionSubtraction
We have parenthesis; 6(4)To remove them, we must multiply 6 by 4 since there is no sign between the two numbers.
6 x 4 = 24
We are now left with:24 + 8
We only have to add, which is the "A" in PEMDAS.Simplify to solve.
24 + 832
32 is your answer.
I hope this helps!
-Ekansh Nimbalkar
First, let's rewrite our problem.
"Find 6x + y when x = 4 and y = 8."
Basically, we need to substitute x with 4 and y with 8.Let's do so.
6(4) + 8 is now our expression. To simplify it, we need to apply PEMDAS:ParenthesisExponentsMultiplicationDivisionAdditionSubtraction
We have parenthesis; 6(4)To remove them, we must multiply 6 by 4 since there is no sign between the two numbers.
6 x 4 = 24
We are now left with:24 + 8
We only have to add, which is the "A" in PEMDAS.Simplify to solve.
24 + 832
32 is your answer.
I hope this helps!
-Ekansh Nimbalkar
Answered by
0
6x+y
=>6×x+y
=>6×4+8
=>24+8
=>32
Therefore ,6x+y is 32
=>6×x+y
=>6×4+8
=>24+8
=>32
Therefore ,6x+y is 32
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