Question

6x2+11x-10 find the zeroe of the following quadratic​

Answer 1

6x^2 + 11x - 10

=> 6x^2 + (15x - 4x) - 10 = 0

=> 6x^2 + 15x - 4x - 10 = 0

=> 3x(2x + 5) - 2(2x + 5) = 0

=> (2x + 5) (3x - 2)

equating both facturs bye 0 we get,

x = -5/2 and x = -2/3

hence, d zeroes r -5/2 and -2/3

Answer 2

Answer:

2/3 and -5/2

Explanation:

6x²+11x²-10

6x²+15x-4x-10

3x(2x+5)-2(2x+5)

(3x-2)(2x+5)

3x-2=0. 2x+5=0.

x=2/3. x=-5/2