6x²+12x+12
middle term help
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Step-by-step explanation:
Zerosofpolynomialare1and1
Step-by-step explanation:
\Large{\underline{\underline{\bf{Given:}}}}
Given:
p(x) = 6x²-12x+6
\Large{\underline{\underline{\bf{To\:Find:}}}}
ToFind:
The zeros of the polynomial
\Large{\underline{\underline{\bf{Solution:}}}}
Solution:
↦ 6x²-12x+6 = 0
↦ By splitting term middle term, we get
6x²-6x-6x+6=0
↦ Taking the common factors out
6x(x-1)-6(x-1)
(x-1)(6x-6) = 0
↦ Either x-1=0
x=1
↦ Or 6x-6=0
x=1
\boxed{\bold{Zeros\:of\:polynomial\:are\:1\:and\:1}}
Zerosofpolynomialare1and1
\Large{\underline{\underline{\bf{Notes:}}}}
Notes:
↦ The zeros of a polynomial can be found out by 3 methods
Factorization method
Splitting the middle term
Completing the square method
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