Question

6x²+13x+2 factorise.. ​

Answer 1

$\huge\bold{\gray{\sf{Answer:}}}$

Explanation:

Above equation is in the form of quadratic equation so it have 2 roots.

Now we factorise it to find roots.

$\bold{\boxed{Form \:of\: Quadratic \:equation=ax²+bx+c}}$

How to factorise..??

step1: Multiply the constant term coefficient of x square.suppose we obtain 'z' after multiplying

step 2:Think of a number whose sum and product makes the 'z'

step 3: now split the middle term by that number which you think.

step 4:At last take common and compare with equal to 0 we obtain the roots .

$= > 6 {x}^{2} + 13x + 2$

$= > 6 {x}^{2} + 12x + x + 2 = 0$

$= > 6x(x + 2) + 1(x + 2) = 0$

$= > (6x + 1)(x + 2) = 0$

$6x + 1 = 0$

$\bold{\purple{x = - \frac{1}{6}}}$

$x + 2 = 0$

$\bold{\purple{x = - 2}}$

Therefore ,the two roots are( x=-1/6,-2)

Answer 2

Step-by-step explanation:

6x²+13x+2 factorise

by splitting middle term

answer in the attachment.