Question

6x² + 17x + 12. Factories.

Answer 1

Answer:

$\boxed{\sf (3x + 4)(2x + 3)}$

Step-by-step explanation:

$\sf Factor \: the \: following: \\ \sf \implies 6{x}^{2} + 17x + 12 \\ \\ \sf The \: coefficient \: of \: {x}^{2} \: is \: 6 \: and \: the \\ \sf constant \: term \: is \: 12. \: The \: product \: of \\ \sf 6 \: and \: 12 \: is \: 72. \\ \sf The \: factors \: of \: 72 \: which \: sum \: to \: 17 \\ \sf are \: 8 \: and \: 9. \\ \\ \sf So, \\ \sf \implies 6{x}^{2} + (8 + 9)x + 12 \\ \\ \sf \implies 6{x}^{2} + 8x + 9x + 12 \\ \\ \sf \implies 2x(3x + 4) + 3(3x + 4) \\ \\ \sf \implies (3x + 4)(2x + 3)$

Answer 2

Answer:

3/2 =x

Step-by-step explanation:

6x^2+17+12.

2×(3x-4) -3(3x-4)

(3x-4) (2x-3)

3x-4=0,X=-4/3

2x-3=0,X=3/2