Question

6x²-3-7x=0 please solve it

Answer 1

Solution is in the attachment....

Answer 2

6x
$6x { }^{2} - 7x - 3 = 0 \\ = > 6x {}^{2} - 9x + 2x - 3 = 0 \\ = > 3x(2x - 3) + 1(2x - 3) = 0 \\ = > (3x + 1)(2x - 3) = 0 \\ = > x = - 1 \div 3 \: \: \: = > x = 3 \div 2$