6x2-3-7x
find zeros of polynomial
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Answer:
Zeroes are 3/2 and -1/3
Step-by-step explanation: This is done by factorisation method
6x^2 - 7x - 3 =0
6x^2 + 2x -9x -3 = 0
2x (3x + 1) - 3 (3x +1) = 0
(2x - 3) (3x+ 1) = 0
Thus, (2x - 3)= 0 or (3x + 1) = 0
Thus, x = 3/2 or x = -1/3
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