Question

6x²-3x-7 verify the relationship between the zeroes and the coefficient
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Answer 1

Answer:

given,

6x²-7x - 3

to find the zeroes of the polynomial,

6x²-7x - 3 = 0

6x²-9x +2x -3 = 0

3x(2x-3) + 1(2x -3) = 0

(3x+1) (2x-3) = 0

x = -1/3 or 3/2

sum of the zeroes = 3/2 - 1/3 = 7/6 = - ( co-efficient of x) / co-efficient of x²

product of the zeroes = -1/3 × 3/2 = -1/2  = constant / co-efficient of x²

Step-by-step explanation:

Answer 2

Answer:

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Step-by-step explanation:

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