Question

6x²-5√3x+3=0 find the root of quadratic equation in the following of factorization method
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Answer 1

Step-by-step explanation:

Step-by-step explanation:6x^2-5√3x+3 =0

Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0

Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms

Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms (6x^2 - 3√3x) - (2√3x + 3)=0

Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms (6x^2 - 3√3x) - (2√3x + 3)=0taking 3x and √3 from 1st and 2nd bracket

Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms (6x^2 - 3√3x) - (2√3x + 3)=0taking 3x and √3 from 1st and 2nd bracket 3x(2x-√3) - √3(2x-3)

Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms (6x^2 - 3√3x) - (2√3x + 3)=0taking 3x and √3 from 1st and 2nd bracket 3x(2x-√3) - √3(2x-3) taking 2x -√3 common

Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms (6x^2 - 3√3x) - (2√3x + 3)=0taking 3x and √3 from 1st and 2nd bracket 3x(2x-√3) - √3(2x-3) taking 2x -√3 common (2x-√3) (3x-√3)

Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms (6x^2 - 3√3x) - (2√3x + 3)=0taking 3x and √3 from 1st and 2nd bracket 3x(2x-√3) - √3(2x-3) taking 2x -√3 common (2x-√3) (3x-√3)therefore the roots of the given quadratic equation are

Step-by-step explanation:6x^2-5√3x+3 =06x^2-3√3x - 2√3x +3=0grouping the terms (6x^2 - 3√3x) - (2√3x + 3)=0taking 3x and √3 from 1st and 2nd bracket 3x(2x-√3) - √3(2x-3) taking 2x -√3 common (2x-√3) (3x-√3)therefore the roots of the given quadratic equation are x= √3/2 and x=√3/3