Question

(6x² +5x-3) ÷ (2x-1)​

Answer 1

Answer:

WE ARRANGE LIKE TERMS

(6x+5x+2x)÷(-1-3)

6x+5x+2x÷1+3

13x÷2

= 6.5

hope this ans help you

Answer 2

The answer is $3x + 4 + \frac{1}{2x - 1}$

Step-by-step explanation:

Given: Divident = (6x² +5x-3)

Divisor = (2x-1)​

To Find: (6x² +5x-3) ÷ (2x-1)​

Solution:

• To find (6x² +5x-3) ÷ (2x-1)​ by polynomial's ling division method

We have (6x² +5x-3) ÷ (2x-1)​ such that we can write and solve it like numerical division as done below.

$\begin{array}{ccc}2x-1& \overline{)\ \ \ \ \ \ \ 6x^{2} +5x-3 \ (}&3x + 4\\&- (6x^{2} - 3x)&\\& \ \ \ \ \ \ \ \ \ \ \ \ \ \ \overline{ \ 8x - 3 \ }&\\& \ \ \ \ \ \ \ \ \ \ \ \ \ - {(8x - 4)}& \\& \ \ \ \ \ \ \ \ \ \ \ \ \ \overline{\ \ \ \ \ \ \ 1 \ \ \ \ \ }&\end{array}$

In this, we have the quotient (3x + 4) while 1 is the reminder. Therefore,

$\frac{6x^{2} + 5x - 3 }{2x-1} = 3x + 4 + \frac{1}{2x - 1}$

Hence, (6x² +5x-3) ÷ (2x-1)​ is $3x + 4 + \frac{1}{2x - 1}$