Question

(6x2 - 5y)
by using identities find the following squares by using the landers ​

Answer 1

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$(a - {b})^{2} = {a}^{2} - 2ab + {b}^{2} \\ \\so,........\\ \\ (6 {x}^{2} - 5 {y})^{2} \\ = (6 {x}^{2})^{2} - 2(6 {x}^{2} )(5y) + (5{y})^{2} \\ = 36 {x}^{4} - 2 \times 30 {x}^{2} y + 25 {y}^{2} \\ = 36 {x}^{4} - 60 {x}^{2} y + 25 {y}^{2}$