Question

6x2-7x+1=0 by quadratic formula​

Answer 1

Answer:

The roots of the quadratic equation are 1, $\frac{1}{6}$ .

Step-by-step explanation:

The roots of a quadratic equation $ax^2+bx+c=0$ is given by the formula,

$x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}$

Given the quadratic equation,

$6x^2-7x+1=0$

We can compare the coefficients to get the following values.

$a=6\\\\b=-7\\\\c=1$

Substituting these values in the formula we get the solutions as,

$x=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\times 6\times 1} }{2\times 6} \\\\=\dfrac{7\pm\sqrt{49-24} }{12} =\dfrac{7\pm\sqrt{25} }{12} =\dfrac{7\pm 5} {12}$

So

$x=\dfrac{7+5}{12}, \dfrac{7-5}{12} = 1,\dfrac{1}{6}$