Question

6x²-7x+1=0 by quadratic formula​

Answer 1

Answer:

The answer is $x=1,\dfrac{1}{6}$

Step-by-step explanation:

   $\boxed{\text{ Quadratic formula } x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}}$

Comparing $6x^2-7x+1=0$ with standard quadratic equation $ax^2+bx+c=0$

We have  $a=6,b=-7,c=1$

Therefore using above mentioned formula, solution is

           $x=\dfrac{-(-7)\pm \sqrt{(-7)^2-4(6)(1)}}{2(6)}$

              $=\dfrac{7\pm \sqrt{49-24}}{12}=\dfrac{7\pm\sqrt{25}}{12}=\dfrac{7\pm 5}{12}\\\\=\dfrac{7+5}{12},\dfrac{7-5}{12}\\=1,\dfrac{1}{6}$