Question

6x2 - 7x-20 factorise

Answer 1

6x²-7x-20

6x²-15x+8x-20

3x(2x-5)+4(2x-5)

(3x+4)(2x-5)

Thnx✌️✌️

Answer 2

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Explanation:

$6 {x}^{2} - 7x - 20 = 0$

It is in the form of a quadratic equation $a {x}^{2} + bx + c = 0$so, here we factorise it to find roots :

How to factorise..??

step1: Multiply the constant term coefficient of x square.suppose we obtain 'z' after multiplying

step 2:Think of a number whose sum and product makes the 'z'

step 3: now split the middle term by that number which you think.

step 4:At last take common and compare with equal to 0 we obtain the roots .

$6 {x}^{2} - 15x + 8x - 20 = 0$

$= > 3x(2x - 5) + 4(2x - 5) = 0$

$(3x + 4)(2x - 5) = 0$

$= > 3x +4 = 0$

$\bold{\red{x = - \frac{4}{3} }}$

$= > 2x - 5 = 0$

$\bold{\red{x = \frac{5}{2} }}$

Hence ,the roots are :$\bold{\red{x = - \frac{4}{3} }}$,$\bold{\red{x = \frac{5}{2} }}$