Question

6x2+7x-3 find the roots​

Answer 1

Answer:

$x=\frac{1}{3}$ or $-\frac{3}{2}$

Step-by-step explanation:

Let us assume that the expression given is equal to 0.

$6x^2+7x-3=0$

Now let us obtain the product of the coefficient of $x^2$ and constant.

$6*(-3)=-18$

Now let us find the factors of -18 as such that its sum is equal to 7.

$9*(-2)=-18$

$9+(-2)=7$

Now split the middle term accordingly.

$6x^2+9x-2x-3=0$

$3x(2x+3)-1(2x+3)=0$

$(3x-1)(2x+3)=0$

$3x-1=0$

$x=\frac{1}{3}$

$2x+3=0$

$x=-\frac{3}{2}$