6x2-7x-3 there are two roots a and b
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Answer:
A and b are - 1/3 and 3/2.
Step-by-step explanation:
6x^2 - 7x - 3 = 0
6x^2 - 9x + 2x - 3 = 0
3x(2x - 3) + 1(2x - 3) = 0
(3x+1) (2x - 3) = 0
3x+ 1 = 0 or 2x - 3 = 0
x = - 1/3. Or x = 3/2
The root are - 1/3 and 3/2
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