Question

6x²-7x-5 factorise..​

Answer 1

(3x - 5)(2x + 1)

Answer:

We have,

$6 {x}^{2} - 7x - 5$

$= 6 {x}^{2} - (10 - 3)x - 5$

$= 6 {x}^{2} - 10x + 3x - 5$

$= 2x(3x) - 2x(5) + 3x - 5$

$= 2x(3x - 5) + 3x - 5$

$= 2x(3x - 5) + 1(3x - 5)$

$= (3x - 5)(2x + 1)$

Answer 2

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Question :-

• 6x²-7x-5 factorise..

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Answer:- (2x-1)(3x-5)

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Step by step explanation:-

$⇢6 {x}^{2} - 7x - 5 \\ \\ ⇢6 {x}^{2} - (10 - 3) x - 5 \\ \\ ⇢6 {x}^{2} - 10x + 3x - 5 \\ \\⇢ 3x(2x - 1) - 5(2x - 1) \\ \\ ⇢(2x - 1)(3x - 5)$

So factor's are (2x-1)(3x-5)

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How to factorise:-

• First spell the middle term .
• And take out common factors.

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