Math, asked by divyasirohiwal, 7 months ago

6x²+ x-2=0 1 answer

Answers

Answered by si2343775

6x^2-x-2

6x^2-4x+3x-2

2x (3x-2)+1 (3x-2)

(2x+1)(3x-2)

Answered by udaybhan2017chauhan

Answer:

$6 {x}^{2} + x - 2 = 0 \\ \\ 6 {x}^{2} + 4x - 3x - 2 = 0 \\ \\ 2x(3x + 2) - 1(3x + 2) = 0 \\ \\ (3x + 2)(2x - 1) =0\\ \\ (x = \frac{ - 2}{3} ),( x = \frac{1}{2} )$

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6x²+ x-2=0 1 answer ​

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6x²+ x-2=0 1 answer