Question

6x²+ x-2=0 1 answer ​

Answer 1

6x^2-x-2

6x^2-4x+3x-2

2x (3x-2)+1 (3x-2)

(2x+1)(3x-2)

Answer 2

Answer:

$6 {x}^{2} + x - 2 = 0 \\ \\ 6 {x}^{2} + 4x - 3x - 2 = 0 \\ \\ 2x(3x + 2) - 1(3x + 2) = 0 \\ \\ (3x + 2)(2x - 1) =0\\ \\ (x = \frac{ - 2}{3} ),( x = \frac{1}{2} )$