Question

6x2-x-2=0 find it's roots of the quadratic equation

Answer 1

Step-by-step explanation:

$6 {x}^{2} - x - 2 = 0 \\ 6 {x}^{2} + 3x - 4x - 2 = 0 \\ 3x(2x + 1) - 2(2x + 1) = 0 \\ (3x - 2)(2x + 1) = 0 \\ (3x - 2) = 0 \: \: \: or \: \: \: (2x + 1) = 0 \\ x = \frac{2}{3} \: \: or \: \: \: x = \frac{ - 1}{2}$

Answer 2

Step-by-step explanation:

Refer the attachment friend