Question

-6x²-x+2 find the root​

Answer 1

Answer:

$- 6 {x}^{2} - x + 2 = 0 \\ = - 6 {x}^{2} - 4x + 3x + 2 = 0 \\ = - 2x(3x + 2) + 1(3x + 2) = 0 \\ = (3x + 2)(1 - 2x) = 0 \\ x = - \frac{2}{3} \: \: and \: \: \frac{1}{2}$

Here is your solution.. Thanks

Answer 2

$\tt\it\bf\it\bm{\mathcal{\fcolorbox{blue}{yellow}{\red{Solution:-}}}}$

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-6x²-x+2=0

➨6x²+x-2=0

➨6x²+4x-3x-2=0

➨2x(3x+2)-1(3x+2)=0

➨(3x+2)(2x-1)=0

➨(3x+2)=0 or (2x-1)=0

➨3x⟹ -2 or 2x⟹1

➨x⟹ -2/3 or x⟹1/2

•°• $\tt{\red{ </strong><strong>x\</strong><strong>:</strong><strong>=</strong><strong>-</strong><strong>2</strong><strong>/</strong><strong>3</strong><strong>\</strong><strong>:</strong><strong>or</strong><strong>\</strong><strong>:</strong><strong>1</strong><strong>/</strong><strong>2</strong><strong> }}$

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