6x²+x-7 factorise it.
Answers
Answer:
Step-by-step explanation:
6x^2-x-2
6x^2-4x+3x-2
2x (3x-2)+1 (3x-2)
(2x+1)(3x-2)
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The quadratic expression x2+x−7x2+x−7, if it is able to be factorised, will factorise into two brackets of the form (ax+b)(cx+d)(ax+b)(cx+d). Expanded, this gives us acx2+adx+bcx+bd=acx2+(ad+bc)x+bdacx2+adx+bcx+bd=acx2+(ad+bc)x+bd, and we can compare this with our original expression to help find these values.
Since our x2x2 coefficient is 66, ac=6.ac=6. Ignoring answers where the values of aa and cc are simply swapped round, and negative values (since we could make those positive by multiplying the whole expression by −1)−1) the possibilities are a=6,a=6, c=1c=1 and a=3,a=3, c=2c=2
So we’re looking for expressions of the form (6x+b)(x+d)(6x+b)(x+d) or